*Here is an ancient problem from Bhaskaracharya’s (Indian Mathematician ) Lilavati:*

A beautiful maiden, with beaming eyes, asks me which is the number that, multiplied by 3, then increased by three-fourths of the product, divided by 7, diminished by one-third of the quotient, multiplied by itself, diminished by 52, the square found, addition of 8,division by 10 gives the number 2?

Well, it sounds complicated, doesn’t it? No, not if you know how to go about ?

Answer:

28

The method of working out this problem is to reverse the whole process.

Labels: Puzzles

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